Nilai lim_(x→0)⁡ (2-2 cos ⁡2x)/x^2=⋯

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Bahas Soal Matematika   »   Limit   ›  

Nilai \( \displaystyle \lim_{x\to 0} \ \frac{2 - 2 \cos 2x}{x^2} = \cdots \)

Pembahasan:

\begin{aligned} \lim_{x\to 0} \ \frac{2 - 2 \cos 2x}{x^2} &= \lim_{x\to 0} \ \frac{2(1 - \cos 2x)}{x^2} \\[8pt] &= \lim_{x\to 0} \ \frac{2(1-(1-2\sin^2 x))}{x^2} \\[8pt] &= \lim_{x\to 0} \ \frac{2(2\sin^2 x)}{x^2} = \lim_{x\to 0} \ \frac{4\sin^2 x}{x^2} \\[8pt] &= 4 \cdot \lim_{x\to 0} \ \frac{\sin x}{x} \cdot \lim_{x\to 0} \ \frac{\sin x}{x} \\[8pt] &= 4 \cdot 1 \cdot 1 \\[8pt] &= 4 \end{aligned}